(5x+3)(2x+1)-x^2-7=y

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Solution for (5x+3)(2x+1)-x^2-7=y equation: 


Simplifying
(5x + 3)(2x + 1) + -1x2 + -7 = y

Reorder the terms:
(3 + 5x)(2x + 1) + -1x2 + -7 = y

Reorder the terms:
(3 + 5x)(1 + 2x) + -1x2 + -7 = y

Multiply (3 + 5x) * (1 + 2x)
(3(1 + 2x) + 5x * (1 + 2x)) + -1x2 + -7 = y
((1 * 3 + 2x * 3) + 5x * (1 + 2x)) + -1x2 + -7 = y
((3 + 6x) + 5x * (1 + 2x)) + -1x2 + -7 = y
(3 + 6x + (1 * 5x + 2x * 5x)) + -1x2 + -7 = y
(3 + 6x + (5x + 10x2)) + -1x2 + -7 = y

Combine like terms: 6x + 5x = 11x
(3 + 11x + 10x2) + -1x2 + -7 = y

Reorder the terms:
3 + -7 + 11x + 10x2 + -1x2 = y

Combine like terms: 3 + -7 = -4
-4 + 11x + 10x2 + -1x2 = y

Combine like terms: 10x2 + -1x2 = 9x2
-4 + 11x + 9x2 = y

Solving
-4 + 11x + 9x2 = y

Solving for variable 'x'.

Combine like terms: y + -1y = 0
-4 + 11x + 9x2 + -1y = 0

The solution to this equation could not be determined.

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